3b^2-19b+28=0

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Solution for 3b^2-19b+28=0 equation:


Simplifying
3b2 + -19b + 28 = 0

Reorder the terms:
28 + -19b + 3b2 = 0

Solving
28 + -19b + 3b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(7 + -3b)(4 + -1b) = 0

Subproblem 1

Set the factor '(7 + -3b)' equal to zero and attempt to solve: Simplifying 7 + -3b = 0 Solving 7 + -3b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -3b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -3b = 0 + -7 -3b = 0 + -7 Combine like terms: 0 + -7 = -7 -3b = -7 Divide each side by '-3'. b = 2.333333333 Simplifying b = 2.333333333

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {2.333333333, 4}

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